Submission #1294603


Source Code Expand

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <string>
#include <cstring>
#include <deque>
#include <list>
#include <queue>
#include <stack>
#include <vector>
#include <utility>
#include <algorithm>
#include <map>
#include <set>
#include <complex>
#include <cmath>
#include <limits>
#include <cfloat>
#include <climits>
#include <ctime>
#include <cassert>
#include <numeric>
#include <functional>
using namespace std;

#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)
#define repq(i,a,n) for(int (i)=(a); (i)<=(n); (i)++)
#define repr(i,a,n) for(int (i)=(a); (i)>=(n); (i)--)
#define all(v) begin(v), end(v)
#define pb(a) push_back(a)
#define fr first
#define sc second
#define INF 2000000000
#define int long long int

#define X real()
#define Y imag()
#define EPS (1e-10)
#define EQ(a,b) (abs((a) - (b)) < EPS)
#define EQV(a,b) ( EQ((a).X, (b).X) && EQ((a).Y, (b).Y) )
#define LE(n, m) ((n) < (m) + EPS)
#define LEQ(n, m) ((n) <= (m) + EPS)
#define GE(n, m) ((n) + EPS > (m))
#define GEQ(n, m) ((n) + EPS >= (m))

typedef vector<int> VI;
typedef vector<VI> MAT;
typedef pair<int, int> pii;
typedef long long ll;

typedef complex<double> P;
typedef pair<P, P> L;
typedef pair<P, double> C;

int dx[]={1, -1, 0, 0};
int dy[]={0, 0, 1, -1};
int const MOD = 1000000007;
ll mod_pow(ll x, ll n) {return (!n)?1:(mod_pow((x*x)%MOD,n/2)*((n&1)?x:1))%MOD;}
int madd(int a, int b) {return (a + b) % MOD;}
int msub(int a, int b) {return (a - b + MOD) % MOD;}
int mmul(int a, int b) {return (a * b) % MOD;}
int minv(int a) {return mod_pow(a, MOD-2);}
int mdiv(int a, int b) {return mmul(a, minv(b));}

namespace std {
    bool operator<(const P& a, const P& b) {
        return a.X != b.X ? a.X < b.X : a.Y < b.Y;
    }
}

vector<string> split(string s, char c) {
    vector<string> ret;
    string temp;
    replace(s.begin(), s.end(), c, ' ');
    stringstream ss(s);
    while(ss >> temp) ret.pb(temp);
    return ret;
}

signed main() {
    string s; getline(cin, s);
    vector<string> vs = split(s, ' ');
    reverse(vs.begin(), vs.end());

    string dummy = "###";
    string prev = dummy;
    vector<string> ans;
    int cnt = 0;
    rep(i,0,vs.size()) {
        if(vs[i] == "not") {
            cnt++;
            if(cnt == 2) {
                if(prev == dummy) {
                    rep(x,0,2) ans.push_back("not");
                }
                cnt = 0;
            }
        }
        else {
            rep(x,0,cnt) ans.push_back("not");
            cnt = 0;
            ans.push_back(vs[i]);
            prev = vs[i];
        }
    }
    rep(x,0,cnt) ans.push_back("not");

    reverse(ans.begin(), ans.end());
    rep(i,0,ans.size()) {
        if(i == 0) cout << ans[i];
        else cout << " " << ans[i];
    }
    cout << endl;
    return 0;
}

Submission Info

Submission Time
Task A - 二重否定除去法則
User tsutaj
Language C++14 (GCC 5.4.1)
Score 100
Code Size 2893 Byte
Status AC
Exec Time 2 ms
Memory 384 KB

Judge Result

Set Name All
Score / Max Score 100 / 100
Status
AC × 19
Set Name Test Cases
All scrambled_00.txt, scrambled_01.txt, scrambled_02.txt, scrambled_03.txt, scrambled_04.txt, scrambled_05.txt, scrambled_06.txt, scrambled_07.txt, scrambled_08.txt, scrambled_09.txt, scrambled_10.txt, scrambled_11.txt, scrambled_12.txt, scrambled_13.txt, scrambled_14.txt, scrambled_15.txt, scrambled_16.txt, scrambled_17.txt, scrambled_18.txt
Case Name Status Exec Time Memory
scrambled_00.txt AC 1 ms 256 KB
scrambled_01.txt AC 1 ms 256 KB
scrambled_02.txt AC 1 ms 256 KB
scrambled_03.txt AC 1 ms 256 KB
scrambled_04.txt AC 1 ms 256 KB
scrambled_05.txt AC 2 ms 384 KB
scrambled_06.txt AC 2 ms 384 KB
scrambled_07.txt AC 2 ms 384 KB
scrambled_08.txt AC 2 ms 384 KB
scrambled_09.txt AC 1 ms 256 KB
scrambled_10.txt AC 1 ms 256 KB
scrambled_11.txt AC 1 ms 256 KB
scrambled_12.txt AC 1 ms 256 KB
scrambled_13.txt AC 2 ms 256 KB
scrambled_14.txt AC 2 ms 256 KB
scrambled_15.txt AC 2 ms 256 KB
scrambled_16.txt AC 2 ms 256 KB
scrambled_17.txt AC 2 ms 256 KB
scrambled_18.txt AC 2 ms 256 KB