Submission #2823586


Source Code Expand

import strutils, sequtils

type
  seqStr = seq[string]
var
  S = stdin.readLine.split
  T = newSeq[string]()

proc judgeC(S: seqStr, n: int): bool =
  for i in 0 ..< n:
    if S[i] != "not":
      return
  return true

proc judgeB(S: seqStr, n: int): bool =
  if S.len == n:
    return judgeC(S, n)

proc judgeA(S: seqStr, n: int): bool =
  if S.len >= n:
    return judgeC(S, n)

while S.len != 0:
  if judgeB(S, 3) or judgeB(S, 2):
    break
  if judgeA(S, 3) or not judgeA(S, 2):
    T.add S[0]
    S.delete 0
  elif judgeA(S, 2):
    S.delete 0, 1

echo (T & S).join(" ")

Submission Info

Submission Time
Task A - 二重否定除去法則
User ToshiroYanagi
Language Nim (0.13.0)
Score 0
Code Size 608 Byte
Status CE

Compile Error

Hint: system [Processing]
Hint: Main [Processing]
Hint: strutils [Processing]
Hint: parseutils [Processing]
Hint: sequtils [Processing]
Main.nim(32, 6) Error: expression 'echo([T & S])' has no type (or is ambiguous)